Higher June 2019 Paper 1 Q24
24 \(\mathrm{f}(x) = \sin(x - 90^\circ)\)
Circle the value of \(\quad \mathrm{f}(0^\circ)\) [1 mark]
- 1
- 0
- \(-\dfrac{1}{2}\)
- \(-1\)
| Answer | Mark | Comments |
|---|---|---|
| \(-1\) | B1 |
24 \(\mathrm{f}(x) = \sin(x - 90^\circ)\)
Circle the value of \(\quad \mathrm{f}(0^\circ)\) [1 mark]
| Answer | Mark | Comments |
|---|---|---|
| \(-1\) | B1 |