Higher June 2019 Paper 2 Q11
11 Joe and Kyle share an amount of money in the ratio \(\quad 7 : n\)
Joe gets 35% of the money.
Work out the value of \(n\). [2 marks]
| Answer | Mark | Comments |
|---|---|---|
| Alternative method 1 | ||
| (65% =) \(\dfrac{13}{20}\) or 7 : 13 | M1 | |
| 13 | A1 | must be selected as the answer |
| Alternative method 2 | ||
| \((100 - 35) \div 35 \times 7\) or \(7 \div 35 \times 100 - 7\) or 20 – 7 | M1 | oe eg \(35 \div 7 = 5\) and \(65 \div 5\) |
| 13 | A1 | must be selected as the answer |
| Alternative method 3 | ||
| \(\dfrac{35}{7} \times n = 100 - 35\) or \(5n = 65\) | M1 | oe equation eg \(\dfrac{7}{n} = \dfrac{35}{100 - 35}\) or \(35n = 455\) |
| 13 | A1 | must be selected as the answer |
Additional guidance
| 35 : 65 with no other valid working | M0 |
| Condone answer £13 | M1A1 |
| Answer 13% or \(13n\) | M1A0 |
| 65% = 0.65 | M0 |
| Alt 2 \(65 \div 35 = 1.9\) \(1.9 \times 7 = 13.3\) (evidence of premature approximation) Answer 13 | M1 A0 |
| Alt 2 \(65 \div 35 = 1.9\) \(1.9 \times 7 = 13\) (assume full calculator value used) | M1 A1 |