Higher June 2019 Paper 2 Q8
8 On the axes, sketch the curve \(\quad y = x^3 - 2\)
You must show the coordinates of the \(y\)-intercept. [2 marks]

| Answer | Mark | Comments |
|---|---|---|
| Fully correct curve and point \((0, -2)\) indicated | B2 | B1 fully correct curve or partially correct curve with point \((0, -2)\) indicated |
Additional guidance
| A partially correct curve must start in the 3rd quadrant and finish in the 1st quadrant, passing through the 4th quadrant not include a section with negative gradient | |
| A fully correct curve must have all the properties of a partially correct curve have only a decreasing gradient to the left of the \(y\)-axis ![]() ![]() Condone straight line segments at each end of the curve | |
| Fully correct curve with \(y\)-intercept labelled \(-2\) | B2 |
| Partially correct curve with \(y\)-intercept labelled \(-2\) | B1 |
| \(y\)-intercept labelled \((-2, 0)\) is incorrect and can score a maximum of B1 | |
| Ignore any numbers on the axes other than the \(y\)-intercept | |
| \(y\)-intercept \((0, -2)\) stated does indicate the point \((0, -2)\) | |
| Unlabelled notches do not indicate the point \((0, -2)\) | |
| A table of values does not indicate the point \((0, -2)\) | |
| Graph consisting only of straight lines | B0 |
A fully correct curve but point \((0, -2)\) is not indicated![]() | B1 |
Partially correct curve with point \((0, -2)\) indicated![]() | B1 |
Fully correct curve with point \((0, -2)\) indicated![]() | B2 |
Partially correct curve with point \((0, -2)\) indicated![]() | B1 |
Curve includes a negative gradient so not partially correct![]() | B0 |






