Higher June 2018 Paper 3 Q25
25 \(ABCDEF\) is a triangular prism which represents part of a hill.
\(ABCF\) is the horizontal rectangular base.
\(D\) is vertically above \(C\).

(a) Work out the height \(CD\). [2 marks]
(b) Jamil walks in a straight line from \(A\) to \(D\).
Work out the size of angle \(DAC\).
You must show your working. [4 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(\tan 6 = \dfrac{CD}{500}\) or \(500 \times \tan 6\) | M1 | oe any letter \(\dfrac{CD}{\sin 6} = \dfrac{500}{\sin 84}\) |
| [52.5, 52.6] or 53 | A1 | May be on diagram |
Additional guidance
Check diagram for angle
| Answer | Mark | Comments |
|---|---|---|
| Alternative method 1 | ||
| \(500^2 + 400^2\) or \(250\,000 + 160\,000\) or \(410\,000\) | M1 | oe |
| \(\sqrt{\text{their } 410\,000}\) or \(\sqrt{500^2 + 400^2}\) or 640.(3…) | M1dep | \(AC\) |
| \(\tan x = \dfrac{[52.5, 52.6] \text{ or } 53}{\text{their } 640.(3..)}\) | M1dep | oe any letter |
| [4.6, 4.75] from correct working | A1 | accept 5 with correct working seen |
| Alternative method 2 | ||
| \(\dfrac{500}{\cos 6}\) or [502.7, 502.8] | M1 | oe \(BD\) |
| \(\sqrt{\left(\dfrac{500}{\cos 6}\right)^2 + 400^2}\) or [642.4, 642.5] | M1dep | \(AD\) |
| \(\sin x = \dfrac{[52.5, 52.6] \text{ or } 53}{\text{their } [642.4, 642.5]}\) | M1dep | oe any letter |
| [4.6, 4.75] from correct working | A1 | accept 5 with correct working seen |
| Alternative method 3 | ||
| \(500^2 + 400^2\) or \(250\,000 + 160\,000\) or \(410\,000\) or \(\dfrac{500}{\cos 6}\) or [502.7, 502.8] | M1 | oe \(BD\) |
| \(\sqrt{\text{their } 410\,000}\) or \(\sqrt{500^2 + 400^2}\) or 640.(3…) or \(\sqrt{\left(\dfrac{500}{\cos 6}\right)^2 + 400^2}\) or [642.4, 642.5] | M1dep | \(AC\) \(AD\) |
| \(\cos x = \dfrac{\text{their } 640.(3...)}{\text{their } [642.4, 642.5]}\) | M1dep | oe any letter |
| [4.6, 4.75] from correct working | A1 | accept 5 with correct working seen |
Additional guidance
| Check diagram for lengths | |
| Beware \(\sin x = \dfrac{52.6}{640.(3...)}\) leads to [4.6, 4.75] | M1M1M0A0 |