Foundation November 2017 Paper 2 Q20
20 In 2015, Han was paid £1350 per month.
In 2016, he
had a 2% increase in his monthly pay
worked 37.5 hours per week
worked for 47 weeks.
Work out Han’s average pay per hour for 2016 [5 marks]
| Answer | Mark | Comments |
|---|---|---|
| Alternative method 1 | ||
| \(1350 \times 0.02\) or 27 | M1 | \(1350 \times 1.02\) or 1377 implies M1M1dep |
| 1350 + their 27 or 1377 | M1dep | |
| their \(1377 \times 12\) or 16 524 | M1 | Monthly pay \(\times\) 12 |
| \(47 \times 37.5\) or 1762.5 | M1 | May be seen as pay \(\div\) 47 \(\div\) 37.5 |
| 9.37… or 9.38 | A1 | Allow 9.40 with method Accept eg £9.38p but not 9.4 |
| Alternative method 2 | ||
| \(1350 \times 12\) or 16 200 | M1 | Monthly pay \(\times\) 12 |
| their 16 200 \(\times\) 0.02 or 324 | M1dep | |
| their 16 200 + their 324 or their 16 200 \(\times\) 1.02 or 16 524 | M1dep | dep on M1M1 |
| \(47 \times 37.5\) or 1762.5 | M1 | May be seen as pay \(\div\) 47 \(\div\) 37.5 |
| 9.37… or 9.38 | A1 | Allow 9.40 with method Accept eg £9.38p but not 9.4 |
| Alternative method 3 | ||
| \(1350 \times 12\) or 16 200 | M1 | |
| \(47 \times 37.5\) or 1762.5 | M1 | May be seen as pay \(\div\) 47 \(\div\) 37.5 |
| their 16 200 \(\div\) their 1762.5 or 9.19... and their 9.19… \(\times\) 0.02 or 0.18… | M1dep | Increase per hour dep on M1M1 |
| their 9.19… + their 0.18… | M1dep | dep on M1M1M1 |
| 9.37… or 9.38 | A1 | Allow 9.40 with method Accept eg £9.38p but not 9.4 |
| Alternative method 4 | ||
| \(47 \times 37.5\) or 1762.5 | M1 | |
| their 1762.5 \(\div\) 12 or 146.87(5) or 146.88 | M1dep | Hours per month |
| 1350 \(\div\) their 146.87(5) or 9.19... and their 9.19… \(\times\) 0.02 or 0.18… | M1dep | Increase per hour |
| their 9.19… + their 0.18… | M1dep | |
| 9.37… or 9.38 | A1 | Allow 9.40 with method Accept eg £9.38p but not 9.4 |
Additional guidance
| Build up steps for 2% or 102% must be correct or have fully correct method shown for any incorrect steps | |
| eg1 1% = 135, 2% = 270, monthly pay = 1620 | M0M0dep |
| eg2 1% = 135, 2% = \(2 \times 135\) = 270, monthly pay = 1620 | M0M0dep |
| eg3 1% = \(1350 \div 100\) = 135, 2% = 270, monthly pay = 1620 | M1M1dep |
| If correct methods or values are seen ignore choice of methods | |
| 27 or 16 200 or 1762.5 | at least M1 |
| 1377 or 324 | at least M1M1 |
| 16 524 | at least M1M1M1 |
| \(1377 \div 4 = 344.25\) \(344.25 \div 37.5 = 9.18\) (unless other correct values seen elsewhere in working) | M1M1dep M0M0A0 |