Foundation June 2018 Paper 3 Q19
19 In an election there were four candidates, J, K, L and M.
Fran is drawing a pie chart to show the results.
The sectors for J and K have been drawn.
(a) Twice as many people voted for L as voted for M.
Complete the pie chart. [3 marks]
(b) Altogether, 16 200 people voted.
How many voted for J? [2 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(360 - 72 - 90\) or 198 | M1 | oe 100(%) \(-\) 20(%) \(-\) 25(%) or 55(%) |
| their \(198 \div 3\) (\(\times\) 2) or 66 or 132 | M1 | Correct line drawn implies M1M1 their \(55 \div 3\) (\(\times\) 2) or 18(.3…) or 36(.6…) or 37 |
| Correct line drawn within 2° and sections labelled correctly | A1 | L in the section with [130°, 134°] M in the section with [64°, 68°] |
Additional guidance
Correct line drawn must be a ruled line for A mark
Angles may be on the diagram
Mark diagram first, if line out of tolerance, check working for method marks
| Answer | Mark | Comments |
|---|---|---|
| \(16\,200 \div 360\) or 45 or \(360 \div 16\,200\) or 0.022… or \(16\,200 \times \dfrac{72}{360}\) | M1 | oe |
| 3240 | A1 |
Additional guidance
| Do not ignore further working | |
| \(16\,200 - 3240 = 12\,960\) | M1A0 |
| \(\dfrac{3240}{16200}\) on answer line | M1A0 |
| \(16\,200 \div 4 \div 90\) | M1 |
| \(16\,200 \div 5\) | M1 |
| 20% of 16 200 without further correct working | M0 |