6 km due South of \(A\) and 6 km due West of \(C\).
Not drawn accurately
Work out the bearing of \(A\) from \(C\). [2 marks]
(b) Here is a scale drawing.
A ship is going to sail from \(D\) to \(E\).
Mia works out that the ship needs to sail on a bearing of 068°
Why must Mia be wrong? [1 mark]
Mark scheme (a)
Answer
Mark
Comments
\(\dfrac{180 - 90}{2}\) or \(\tan^{-1} \dfrac{6}{6}\) or 45
M1
oe may be seen on diagram eg \(\sin^{-1}\left(\dfrac{6}{\sqrt{72}}\right)\)
315
A1
SC1 answer of 135 (bearing of \(C\) from \(A\))
Additional guidance
\(\tan \dfrac{6}{6}\) unless recovered
M0
Mark scheme (b)
Answer
Mark
Comments
Correct explanation that the ship would be on land or 068° is the bearing of \(D\) from \(E\) or the bearing must be over 180° or the actual bearing is [246, 250]°
B1
eg that would take the ship over land 068° is from \(E\) 068° is the bearing from \(E\) to \(D\) the bearing is 248°
Additional guidance
Ignore irrelevant statements and compass points eg bearings go clockwise, bearings are measured from north, NE, south west
Do not accept incorrect statement or bearing alongside a correct statement
Bearings measured or stated outside of [246, 250]° range
