Higher November 2022 Paper 1 Q3
3 \(0.203 = \dfrac{1}{5} + x\)
Circle the value of \(x\). [1 mark]
- \(\dfrac{1}{300}\)
- \(\dfrac{1}{3000}\)
- \(\dfrac{3}{100}\)
- \(\dfrac{3}{1000}\)
| Answer | Mark | Comments |
|---|---|---|
| \(\dfrac{3}{1000}\) | B1 |
3 \(0.203 = \dfrac{1}{5} + x\)
Circle the value of \(x\). [1 mark]
| Answer | Mark | Comments |
|---|---|---|
| \(\dfrac{3}{1000}\) | B1 |