Foundation November 2018 Paper 1 Q17
17
(a) Laura wants to work out \(\quad\) 3% of 1700
Her method is \(\quad 1700 \times 0.3\)
Is her method correct?
Tick a box.
- Yes
- No
Give a reason for your answer. [1 mark]
(b) Laura also wants to work out \(\quad \dfrac{30}{29}\) of 60
Her answer is 58
Is her answer correct?
Tick a box.
- Yes
- No
Give a reason for your answer. [1 mark]
| Answer | Mark | Comments |
|---|---|---|
| Ticks ‘No’ and gives correct explanation indicating her error | B1 | eg It should be 0.03 0.3 would give 30% It’s 10 times too big You need to divide by 10 as well |
Additional guidance
| ‘Yes’ ticked | B0 |
| If ‘No’ is not ticked, explanation must include a decision that the statement is incorrect ‘No’ not ticked and ‘it should be 0.03’ (only implies ‘No’) ‘No’ not ticked and ‘it should be 0.03 so she is wrong’ | B0 B1 |
| It is not sufficient to only show a different correct method, eg ‘No’ and ‘divide by 100 and multiply by 3’ eg ‘No’ and ‘she has divided by 10 and multiplied by 3 but she should have divided by 100 then multiplied by 3’ | B0 B1 |
| ‘No’ and ‘\(1700 \times 0.03\)’ (a correction of Laura’s method) | B1 |
| Calculating the correct answer must come with the correct evaluation of Laura’s method eg ‘No’ and ‘should be 51’ eg ‘No’ and ‘Laura gets 510 but it should be 51’ | B0 B1 |
| Answer | Mark | Comments |
|---|---|---|
| Ticks ‘No’ and gives correct explanation | B1 | eg \(\dfrac{30}{29}\) is bigger than 1 58 is from \(\dfrac{29}{30}\) the answer would have to be bigger than 60 it will be a decimal |
Additional guidance
| ‘Yes’ ticked | B0 |
| ‘60 doesn’t divide by 29’ oe | B0 |
| ‘No’ ticked and ‘the numerator and denominator are wrong way round’ | B1 |
| If ‘No’ is not ticked, explanation must include a decision that the statement is incorrect ‘No’ not ticked and ‘it should be more than 60’ (only implies ‘No’) ‘No’ not ticked and ‘it should be more than 60 so she is wrong’ | B0 B1 |
| ‘No’ ticked and \(60 \div 29 = 2.(\ldots)\) then \(2.(\ldots) \times 30 = [60, 70)\) accept 2 r2 for 2.( …) | B1 |
| ‘No’ ticked and \(30 \div 29 = 1.(\ldots)\) and \(1.(\ldots) \times 60 = [60, 70)\) accept 1 r1 for 1.( …) | B1 |
| ‘No’ ticked and ‘because it’s a top heavy fraction’ ‘No’ ticked and ‘because it’s a top heavy fraction so it’s bigger than 1’ | B0 B1 |
| ‘No’ ticked and ‘\(1\dfrac{1}{29} \times 60\)’ ‘No’ ticked and ‘\(1\dfrac{1}{29} \times 60\) so the answer is over 60’ | B0 B1 |