Foundation June 2019 Paper 2 Q5
5 Which is longer, \(\quad \dfrac{3}{4}\) of a day \(\quad\) or \(\quad\) 1000 minutes?
You must show your working. [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| Alternative method 1 | ||
| \(24 \div 4 \times 3\) or 18 | M1 | oe |
| their \(18 \times 60\) or 1080 | M1dep | oe 1080 implies M2 |
| 1080 and \(\dfrac{3}{4}\) (of a day) | A1 | |
| Alternative method 2 | ||
| \(24 \times 60\) or 1440 | M1 | oe |
| their \(1440 \div 4 \times 3\) or 1080 | M1dep | oe 1080 implies M2 |
| 1080 and \(\dfrac{3}{4}\) (of a day) | A1 | |
| Alternative method 3 | ||
| \(24 \div 4 \times 3\) or 18 | M1 | oe |
| \(1000 \div 60\) or 16(.6…) or 16.7 or 17 | M1 | may be seen in either order (M marks not dependent) [16 h 36 m, 16 h 42 m] implies division 16 or 17 may be embedded |
| 16(.6…) or 16.7 or 17 or [16 h 36 m, 16 h 42 m] and 18 and \(\dfrac{3}{4}\) (of a day) | A1 | 16 or 17 may be embedded |
| Alternative method 4 | ||
| \(24 \times 60\) or 1440 | M1 | oe |
| \(1000 \div\) their 1440 (\(\times\) 100) or \(\dfrac{25}{36}\) or 0.69… or 69(…)% | M1dep | oe \(\dfrac{25}{36}\) or 0.69… or 69(…)% implies M2 |
| \(\dfrac{25}{36}\) and \(\dfrac{27}{36}\) and \(\dfrac{3}{4}\) (of a day) or 0.69… and 0.75 and \(\dfrac{3}{4}\) (of a day) or 69(…)% and 75% and \(\dfrac{3}{4}\) (of a day) | A1 | |
Additional guidance
| Ignore units for the M marks but they must be correct, if given, for the A mark | |
| \(\dfrac{3}{4}\) of 24 is insufficient method unless a correct method or 18 is seen | |
| Once \(1000 \div 60\) or 16 or 16.6… or 16.7 or 17 is seen in Alt method 3, ignore any incorrect conversion to hours and minutes. If the student only shows hours and minutes, they must be in the given range. | |
| Do not accept \(\dfrac{3}{4}\) (of a day) in equivalent form eg 1080 or 18 | A0 |