Foundation June 2019 Paper 1 Q29
29 Here is the graph of \(y = x^2 - 2x - 3\)
(a) Write down the coordinates of the turning point on the graph of \(y = x^2 - 2x - 3\) (1)
(b) Use the graph to find the roots of the equation \(x^2 - 2x - 3 = 0\) (2)
| Answer | Mark | Mark scheme |
|---|---|---|
| 1, –4 | B1 | cao |
Additional guidance
Brackets are given on the answer line, ignore any extra brackets seen
| Answer | Mark | Mark scheme |
|---|---|---|
| –1 and 3 | B2 | for both correct answers |
| (B1 | for one correct solution or \((x + 1)(x - 3)\) or \((-1, 3)\)) |