Foundation June 2024 Paper 3 Q29
29 \(w = 40 - t^2\)
(a) Calculate the value of \(w\) when \(\ t = -5\) (2)
\[p = \frac{h - 5}{3}\]
(b) Make \(h\) the subject of the formula. (2)
| Answer | Mark | Mark scheme |
|---|---|---|
| 15 | M1 | for correct substitution, eg \(40 - (-5)^2\) |
| A1 | cao |
Additional guidance
Condone missing brackets
| Answer | Mark | Mark scheme |
|---|---|---|
| \(h = 3p + 5\) | M1 | for a correct first step, eg \(3p = h - 5\) or for isolating the \(\dfrac{h}{3}\) term, eg \(p + \dfrac{5}{3} = \dfrac{h}{3}\) |
| A1 | for \(h = 3p + 5\) oe eg \(h = 3\left(p + \dfrac{5}{3}\right)\) |
Additional guidance
Award M1 for \(3p + 5\) without seeing \(h = 3p + 5\)