Higher November 2023 Paper 3 Q10
10 Make \(m\) the subject of \(k = p + \dfrac{2m}{5}\) (3)
| Answer | Mark | Mark scheme |
|---|---|---|
| \(m = \dfrac{5(k - p)}{2}\) | M1 | for a correct first step, eg \(k - p = \dfrac{2m}{5}\) or \(5k = 5p + 2m\) or \(\dfrac{k}{2} = \dfrac{p}{2} + \dfrac{m}{5}\) |
| M1 | for a correct statement isolating \(2m\), \(-2m\), \(\dfrac{m}{5}\) or \(-\dfrac{m}{5}\) eg \(5(k - p) = 2m\) or \(5k - 5p = 2m\) or \(\dfrac{m}{5} = \dfrac{k}{2} - \dfrac{p}{2}\) | |
| A1 | for \(m = \dfrac{5(k - p)}{2}\) oe |
Additional guidance
Steps must be carried out not just intention seen
Accept statements with \(m\) on the right hand side, eg \(\dfrac{5(k - p)}{2} = m\)