Higher June 2024 Paper 3 Q18

AQACurrent spec4 marksAdvanced Trigonometry

18 Here is triangle A.

Triangle A with sides 11 cm and 7 cm; the angle of 35° is opposite the 7 cm side and angle x is opposite the 11 cm side

Not drawn accurately

(a) Use the sine rule to show that \(\quad x = 64^\circ \quad\) to the nearest degree. [3 marks]
(b) Here is triangle B.
Triangle B with sides 11 cm and 7 cm meeting at an angle of 35°; angle w is between the 7 cm side and the third side

Not drawn accurately

Anna thinks that \(w\) must be \(64^\circ\) to the nearest degree.

She says,

“This is because triangle B has two sides and one angle the same as triangle A.”

Without further calculation, is she correct?

Tick a box.

  • Yes
  • No

Give a reason for your answer. [1 mark]