Foundation November 2022 Paper 1 Q14
14 Jenny drives from London to Swindon at an average speed of 54 miles per hour.
She drives for \(1\dfrac{1}{2}\) hours.
(a) Work out the distance from London to Swindon. (2)
Aleksy is using a map.
The map has a scale of \(\;1 : 25\,000\)
On the map a road has a length of 6 cm.
(b) Work out the length, in kilometres, of the real road. (3)
| Answer | Mark | Mark scheme |
|---|---|---|
| 81 | M1 | for \(54 \times [\text{time}]\) eg \(54 \times 1\dfrac{1}{2}\) oe, or \(54 + 54 \div 2\) oe |
| A1 | cao |
Additional guidance
[time] could be \(1\dfrac{1}{2}\) oe or any other time that has been changed from \(1\dfrac{1}{2}\), eg 90 (mins) or 1.30 or 130
| Answer | Mark | Mark scheme |
|---|---|---|
| 1.5 | P1 | for use of scale eg \(6 \times 25\,000\ (= 150\,000)\) or for \(25\,000 \div 100\,000\ (= 0.25)\) or \(25\,000 \div 100\ (= 250)\) or \(25\,000 \div 1000\ (= 25)\) |
| P1 | for \(\text{``}150\,000\text{''} \div 100\,000\ (= 1.5)\) or \(\text{``}150\,000\text{''} \div 100\ (= 1500)\) or \(\text{``}150\,000\text{''} \div 1000\ (= 150)\) or for \([0.25] \times 6\ (= 1.5)\) | |
| A1 | for 1.5 oe |
Additional guidance
[0.25] could be found by dividing 25 000 by 100 (= 250) or dividing 25 000 by 1000 (= 25)