Foundation November 2024 Paper 3 Q10
10
(a) Solve \(\quad \dfrac{c}{3} = 15\) [1 mark]
(b) Solve \(\quad 4(2d - 5) = 28\) [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| 45 | B1 |
| Answer | Mark | Comments |
|---|---|---|
| Alternative method 1: Expands bracket first | ||
| \(8d - 20\) | M1 | oe expression eg \(8 \times d - 20\) |
| their \(8d = 28 + \text{their } 20\) or \(8d = 48\) | M1 | their 20 cannot be zero |
| 6 | A1ft | ft M0M1 or M1M0 |
| Alternative method 2: Divides by 4 first | ||
| \(2d - 5 = \dfrac{28}{4}\) or \(2d - 5 = 7\) | M1 | |
| \(2d =\) their \(7 + 5\) or \(2d = 12\) | M1 | their 7 cannot be 28 |
| 6 | A1ft | ft M0M1 or M1M0 |
Additional guidance
| Alt 1 \(6d - 5 = 28\) \(6d = 33\) \(d = \dfrac{33}{6}\) | M0 M1 A1ft |
| Alt 2 \(2d - 5 = 24\) \(2d = 29\) \(d = 14.5\) | M0 M1 A1ft |
| Answer 6 from trial | M1M1A1 |
| Embedded answer \(4(2 \times 6 - 5) = 28\) | M1M1A0 |
| ft answers correct to 1 dp or better |