Foundation November 2024 Paper 2 Q12
12
(a) Work out the value of \(\quad x^2 + 7x \quad\) when \(\quad x = -4\) [2 marks]
(b) Rearrange \(\quad y = w - 1 \quad\) to make \(w\) the subject. [1 mark]
(c) Simplify fully \(\quad 4(a + 2) + a\) [2 marks]
| Answer | Mark | Comments |
|---|---|---|
| \((-4)^2 + 7 \times -4\) or \(-4(-4 + 7)\) or 16 or \(-28\) | M1 | oe eg \((-4)^2 + 7(-4)\) |
| \(-12\) | A1 | SC1 \(-44\) |
Additional guidance
| SC is for \(-4^2 + 7 \times -4 = -16 - 28 = -44\) | |
| Embedded 16 or \(-28\) seen eg \(16 + 7x\) without correct answer | M1A0 |
| Values may be implied eg1 \((-4)^2 + 7 \times 4 = 44\) 16 is implied eg2 only answer 44 | M1A0 M0A0 |
| Further correct work eg \(16 - 28 = -12\), Answer \(3x\) | M1A1 |
| Further incorrect work eg \(16 - 28 = -12\), Answer \(-12x\) | M1A0 |
| \(+-28\) is the same as \(-28\) | M1 |
| Only \(-4^2 + 7 \times -4\) | M0A0 |
| \(-4^2 + 7 \times -4 = -16 + 28 = 12\) | M0A0 |
| \(16x\) does not imply 16 | M0A0 |
| Answer | Mark | Comments |
|---|---|---|
| \(y + 1\) or \(1 + y\) | B1 |
| Answer | Mark | Comments |
|---|---|---|
| \(4a + 8\) or \(8 + 4a\) or \(5a\) | M1 | |
| \(5a + 8\) or \(8 + 5a\) | A1 |
Additional guidance
| Further incorrect work or simplification eg \(5a + 8\), Answer \(13a\) | M1A0 |