A2 June 2024 Q5
5.
The region \(R\) in the \(z\)-plane is given by\[\left\{z \in \mathbb{C} : 0 < \arg z < \frac{\pi}{4}\right\}\]
| Scheme | Marks | AO |
|---|---|---|
| \(|x + (y - 3)\mathrm{i}| = 2|x + y\mathrm{i}| \Rightarrow x^2 + (y - 3)^2 = 4\left(x^2 + y^2\right)\) | M1 | 3.1a |
| \(\Rightarrow x^2 + y^2 - 6y + 9 = 4x^2 + 4y^2 \Rightarrow x^2 + y^2 + 2y - 3 = 0\) in any order | M1 A1 | 1.1b 1.1b |
| (3) |
Notes
M1: Substitutes \(z = x + y\mathrm{i}\) into the equation and applies the modulus to obtain an equation with no i's. Must have dealt with the i\(^2\) correctly. Condone not squaring the 2.
M1: Expands and gathers terms. Must have an \(x^2\) and \(y^2\) after simplifying so that it is an equation of a circle.
A1: Cancels common factor 3 to obtain the equation shown. ISW if they make errors trying to complete the square.
Note: Any letters may be used not just \(x\) and \(y\)
Alt (a)
| Scheme | Marks | AO |
|---|---|---|
| Points are twice as far from 3i as from 0 so i and −3i are diametrically opposite points. | M1 | 3.1a |
| So radius is \(\dfrac{|\mathrm{i} - (-3\mathrm{i})|}{2} = 2\) and centre is \(\dfrac{\mathrm{i} - 3\mathrm{i}}{2} = -\mathrm{i}\) | M1 | 1.1b |
| Hence equation is \(x^2 + (y + 1)^2 = 4\) | A1 | 1.1b |
| (3) |
M1: Identifies two diametrically opposite points on the circle by understanding the geometry of the situation.
M1: Finds the radius and centre of the circle from their points, dotted or solid line
A1: Correct equation need not expand, but should be in simplest form.
| Scheme | Marks | AO |
|---|---|---|
![]() | ||
| Circle drawn with the inside shaded | M1 | 2.2a |
| Correct circle drawn for their equation. Implied by the position of the centre and radius. Inside shaded. | A1ft | 3.1a |
| (2) |
Notes
M1: Circle drawn anywhere and the inside shaded
A1ft: Correct circle drawn for their equation. Implied by the position of the centre and radius. Inside shaded.
| Scheme | Marks | AO |
|---|---|---|
| A point \(z\) is mapped to a point with 3 times the argument… Rotate every point by 2 times the argument | B1 | 2.4 |
| … and with modulus as the modulus of the cube of \(z\). | B1 | 2.5 |
| (2) |
Notes
B1: Identifies that the argument triples in size.
B1: Identifies that the modulus scales according to the modulus of \(z\) cubed.
| Scheme | Marks | AO |
|---|---|---|
![]() | ||
| Sector from \(O\) along the real axis, indicated by some shading, in an anticlockwise direction | M1 | 1.1b |
| Correct sector, angle must be stated or implied by the diagram | A1 | 2.2a |
| (2) | ||
| (9 marks) |
Notes
M1: A sector centre \(O\) and starting along the real axis and in an anticlockwise direction. Must be some shading to represent the region, dotted or solid line
A1: Correct sector shaded and the angle stated or implied

