October 2021 Paper 1 Q5
5 The fuel consumption of a car, \(C\) miles per gallon, varies with the speed, \(v\) miles per hour. Jamal models the fuel consumption of his car by the formula
\(C = \frac{12}{5}v - \frac{3}{125}v^2\), for \(0 \leqslant v \leqslant 80\).
Amaya’s car does more miles per gallon than Jamal’s car. She proposes to model the fuel consumption of her car using a formula of the form
\(C = \frac{12}{5}v - \frac{3}{125}v^2 + k\), for \(0 \leqslant v \leqslant 80\), where \(k\) is a positive constant.
| Scheme | Marks |
|---|---|
| Maximum speed of the car or model will show consumption eventually becoming negative or model may not apply for above 80 mph | B1 |
| [1] |
Notes
B1: or, eg, doesn't drive faster than 80, or speed limit
Condone eg “Maximum number of miles car can drive”
| Scheme | Marks |
|---|---|
| \(\dfrac{\mathrm{d}}{\mathrm{d}v}\left(\frac{12}{5}v - \frac{3}{125}v^2\right) = 0\) \(\left(\Rightarrow \frac{12}{5} - \frac{6v}{125} = 0\right)\) | M1 |
| \(v = 50\) | A1 |
| \(\dfrac{\mathrm{d}^2}{\mathrm{d}v^2}\left(\frac{12}{5}v - \frac{3}{125}v^2\right) = -\frac{6}{125}\) when \(v = 50\) or any correct method showing that SP is a maximum | M1 |
| Maximum speed is 50 mph | A1 |
| [4] |
Notes
M1: Attempt differentiate \(C\) & equate to 0
M1: Must be correct
A1: Units essential. Dep only on 1st M1
Alternative method 1
| Scheme | Marks |
|---|---|
| \(v = -\dfrac{b}{2a}\) \(\left(= -\dfrac{\frac{12}{5}}{2 \times \frac{(-3)}{125}}\right)\) Attempt complete square | M1 |
| \(v = 50\) | A1 |
| Coefficient of \(v^2\) negative, hence stationary point is a maximum | M1 |
| Maximum speed is 50 mph | A1 |
A1: Units essential
Alternative method 2
| Scheme | Marks |
|---|---|
| \(\frac{12}{5}v - \frac{3}{125}v^2 = 0\) (\(v = 0\) or 100) & | M1 |
| Correct sketch graph & \(v = 50\) | B1 |
| \(v = 50\) seen on graph as giving maximum | M1 |
| Maximum speed is 50 mph | A1 |
M1: Working must be seen
B1: NB. This mark can be gained without working to justify the graph.
A1: Units essential
| Scheme | Marks |
|---|---|
| \(v = 0\) does not give \(C = 0\) oe | B1 |
| [1] |
Notes
B1: They will not consume fuel at 0 mph oe
| Scheme | Marks |
|---|---|
| eg \(k\left(\frac{12}{5}v - \frac{3}{125}v^2\right)\) | B1 |
| with any \(k \gt 1\) | B1 |
| [2] |
Notes
or "Increase both constants by the same factor" B1B1
or with numerical value of \(k\) (\(\gt 1\)) B1B1
SC: “Increase both constants” B1B0
Alternative method
| Scheme | Marks |
|---|---|
| eg \((1 + k)\left(\frac{12}{5}v - \frac{3}{125}v^2\right)\) | B1 |
| where \(k \gt 0\) | B1 |