Numeracy Intermediate November 2020 Unit 2 Q7
7. In May 2018, the population of Wales was approximately 3 150 000.
Of this population, approximately 286 500 people were aged 75 or over.
In May 2018, a survey in Wales found the following:
- 85% of the population of Wales used the internet,
- 99% of people aged 16 to 24 used the internet,
- 40% of people aged 75 or over used the internet.
(a) In May 2018, how many people in Wales did not use the internet? [2]
(b) Of all the internet users in Wales in May 2018, what percentage were aged 75 or over?
Give your answer correct to 2 significant figures.
You must show all your working. [5]
Give your answer correct to 2 significant figures.
You must show all your working. [5]
| Scheme | Marks | Comments |
|---|---|---|
| 3 150 000 - 0.85 × 3 150 000 (=3 150 000 - 2 677 500) or 0.15 × 3 150 000 | M1 | |
| 472 500 (people) | A1 |
| Scheme | Marks | Comments |
|---|---|---|
| (Aged 75 or over who used internet) (0.4 × 286 500 =) 114 600 | B1 | May be implied in further working. |
| (Population who used the internet) (0.85 × 3 150 000 =) 2 677 500 | B1 | May be implied in further working. FT 3 150 000 – ‘their 472 500’ (from (a)) |
| \(\dfrac{114\ 600}{2\ 677\ 500}\) ( × 100) | M1 | FT provided both 0.4 × 286 500 and 0.85 × 3 150 000 attempted |
| 4.3 (%) | A2 | Must be correct to 2 significant figures. A1 for 4.28(0...%) or from correct working 4(%) or 4.2(%) If no marks, award SC1 for an answer of 9.1(%) from \(\dfrac{286\ 500}{3\ 150\ 000}\) × 100 If B1 awarded, also award SC1 for 3.638...(%) or 10.7...(%) or with appropriate rounding or truncation OR SC2 for 3.6 (%) or 11 (%), from: \(\dfrac{114600}{3150000}\) × 100 = 3.638...(%) = 3.6 (%) or \(\dfrac{286500}{2677500}\) × 100 = 10.7...(%) = 11 (%) |