Intermediate November 2018 Unit 2 Q8
8.
(a) Calculate the approximate difference in length between 1 mile and 1·5 km.
Give your answer in metres. [3]
Give your answer in metres. [3]
(b) Convert an area of 4 m2 into cm2. [2]
4 m2 = ……………………… cm2
| Scheme | Marks | Comments |
|---|---|---|
| (1 mile =) 8/5(km) or 1600(m) or equivalent | B1 | For sight of a correct conversion e.g. 5 miles = 8 km , 1 km = 5/8 mile. Allow more accurate correct approximations (for all marks) only if in the range [1609(m) to 1610(m)] No FT from an incorrect conversion. |
| (Difference =) \(\dfrac{8}{5}\) × 1000 – 1·5 × 1000 | M1 | Allow M1 for \(\dfrac{8}{5}\) − 1·5 (= 0·1) or equivalent. |
| 100 (metres) | A1 | Allow –100 (metres). If no marks gained then allow SC1 for sight of (1·5 × 5/8) |
| Scheme | Marks | Comments |
|---|---|---|
| 4 × 1002 | M1 | Also for alternative correct methods e.g. (A 4x1 rectangle followed by) a 400×100 calculation, 200 × 200, etc. |
| = 40000 | A1 |