Pythagoras: WJEC GCSE Intermediate November 2018 Unit 2 Q16

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Intermediate November 2018 Unit 2 Q16

WJECIntermediateCurrent spec4 marksPythagoras

16. The perimeter of a square is 76·4 m.

Calculate the length of its diagonal.
You must show all your working. [4]

Mark scheme

Scheme	Marks	Comments
(Length of side = \(\dfrac{76{\cdot}4}{4}\) =) 19·1(m)	B1
(diagonal² =) 19·1² + 19·1²	M1	F.T. ‘their derived length of side’ (not 76·4)
diagonal² = 729·6(2) or (diagonal =) √729·6(2)	A1	Diagonal = 729·6(2) is A0 unless corrected in further work
(diagonal =) 27·0(..)(m) or 27(m)	A1	F.T. 'their 729.6' provided M1 awarded and their answer is greater than 19·1. Award SC2 for a final answer of 108(·0…)(m) (from using 76·4(m) as side length) BUT In this case there is no credit given for sight of 19·1.