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Higher November 2023 Unit 2 Q1

WJECHigherCurrent spec4 marksDrawing & Using Graphs

1. The table below shows some of the values of \(y = x^2 + 4x + 5\) for values of \(x\) from –4 to 1.

\(x\)–4–3–2–101
\(y = x^2 + 4x + 5\)5225
(a) Complete the table by finding the value of \(y\) for \(x\) = –2 and for \(x\) = 1. [2]
(b) On the graph paper below, draw the graph of \(y = x^2 + 4x + 5\) for values of \(x\) from –4 to 1. [2]
Graph paper with x-axis from -4 to 1 and y-axis from -2 to 12