Factorising: WJEC GCSE Higher November 2021 Unit 2 Q8

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Higher November 2021 Unit 2 Q8

WJECHigherCurrent spec3 marksFactorising Solving Quadratics

8. Factorise \(x^2 - 4x - 12\), and hence solve \(x^2 - 4x - 12 = 0\). [3]

Mark scheme

Scheme	Marks	Comments
\((x - 6)(x + 2)\)	B2	B1 for \((x \ldots 6)(x \ldots 2)\).
\((x =)\ 6\) AND \((x =)\ -2\)	B1	Strict F.T. from their brackets. Penalise change of letter −1. Allow the following. B2 for \(x - 6\ (=0)\) AND \(x + 2\ (=0)\) (B1) \((x =)\ 6\) AND \((x =)\ -2\) (B1) B1 for \(x + 6\ (=0)\) AND \(x - 2\ (=0)\) (B0) \((x =)\ -6\) AND \((x =)\ 2\) (B1) FT B1 if only \((x =)\ 6\) AND \((x =)\ -2\) seen. (B1) Use of quadratic formula would only lead to this B1. Mark final answer.