Foundation June 2017 Unit 2 Q20
20. ABCF is a rectangle.
CDEF is a trapezium.
BD is a straight line.
Diagram not drawn to scale
AB = 7 cm, BD = 9 cm and DE = 3 cm.
The perimeter of rectangle ABCF is 24 cm.
Calculate the area of the trapezium CDEF.
You must show all your working. [4]
From the formula list: Area of trapezium \(= \dfrac{1}{2}(a+b)h\)
| Scheme | Marks | Comments |
|---|---|---|
| (BC =) (24 – 2x7)/2 | M1 | Lengths may be seen on diagram. A clearly shown incorrect method for finding CD is M0A0 otherwise CD=4(cm) implies this M1A1. |
| (BC =) 5(cm) | A1 | |
| (Area CDEF =) \(\dfrac{(7 + 3)}{2}\) × (9 – 5) or equivalent. | M1 | F.T. ‘their derived 5’ OR F.T. \(\dfrac{(7 + 3)}{2}\) × ‘their stated or shown length CD (<9)’ Allow M1 for correct intent e.g. ‘7 + 3 × 4 ÷ 2’ then A0. |
| = 20 (cm2) | A1 | Ignore any further attempt to find total area of whole shape if area of CDEF seen. |