Intermediate November 2017 Unit 1 Q7
7. \(ABCD\) is a quadrilateral.
\(A\hat{B}C = 93^\circ\), \(B\hat{C}D = 122^\circ\) and \(A\hat{D}C = 85^\circ\).
Points \(P\) and \(Q\) lie on the quadrilateral as shown, such that \(AP = AQ\).
Prove that triangle \(APQ\) is an equilateral triangle.
You must show all your working. [5]

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| Scheme | Marks | Comments |
|---|---|---|
| This is a ‘proof’ question so the work for the M1 mark must be seen before the A1 mark can be awarded. | ||
| (BÂD =) 360 – ( 85 + 122 + 93) | M1 | |
| = 60(°) | A1 | |
| (APQ = AQP = ) \(\dfrac{180 - 60}{2}\) | M1 | F.T. ‘their 60’ only if previous M1 awarded. Allow reference to isosceles triangle. |
| = 60(°) | A1 | |
| A convincing statement AND the three angles shown as, or stated to be 60(°) | E1 | Independent of previous marks. Must refer to three (all) angles being equal. Three angles of 60° must be shown or stated as part of a convincing statement. Reference to equal sides alone is E0. |