FDPR Mixed Context: WJEC GCSE Intermediate June 2025 Unit 1 Q4

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Intermediate June 2025 Unit 1 Q4

WJECIntermediateCurrent spec3 marksFDPR Mixed Context

4. Write 0·62, 68% and \(\dfrac{13}{20}\) in ascending order.

You must show all your working. [3]

Smallest value ⟶ Greatest value

Mark scheme

Scheme	Marks	Comments
Showing 62(%) and (68%) and 65(%) OR \(\dfrac{62}{100}\) and \(\dfrac{68}{100}\) and \(\dfrac{65}{100}\) OR (0·62) and 0·68 and 0·65 OR three correct calculations for a common amount.	B2	Award B2 for one of the following: all correct % ( \(\dfrac{62}{100}\) or \(\dfrac{65}{100}\) must be shown as 62% or 65%) all correct fractions with a common denominator (could include decimals as numerators and denominators) all correct decimals correct work using a common amount a valid combination that allows full comparison (e.g. \(\dfrac{13}{20}\) = 0·65 and 65%). Award B1 for one of the following: one correct conversion (percentage or decimal) two correct fractions with a common denominator two correct calculations for a common amount.
0·62 \(\dfrac{13}{20}\) 68% in order	B1	Allow any unambiguous indication (e.g. ‘converted’ values.) Correct answer with no incorrect conversions seen gains the final B1. If incorrect conversions seen, then strict FT of ‘their work’ only if B1 gained. Unsupported correct answer gains final B1 only.

Scheme

Marks

Comments

Showing
62(%) and (68%) and 65(%)
OR \(\dfrac{62}{100}\) and \(\dfrac{68}{100}\) and \(\dfrac{65}{100}\)
OR (0·62) and 0·68 and 0·65
OR three correct calculations for a common amount.

Award B2 for one of the following:

all correct % ( \(\dfrac{62}{100}\) or \(\dfrac{65}{100}\) must be shown as 62% or 65%)
all correct fractions with a common denominator (could include decimals as numerators and denominators)
all correct decimals
correct work using a common amount
a valid combination that allows full comparison (e.g. \(\dfrac{13}{20}\) = 0·65 and 65%).

Award B1 for one of the following:

one correct conversion (percentage or decimal)
two correct fractions with a common denominator
two correct calculations for a common amount.

0·62 \(\dfrac{13}{20}\) 68% in order

Allow any unambiguous indication (e.g. ‘converted’ values.)
Correct answer with no incorrect conversions seen gains the final B1.
If incorrect conversions seen, then strict FT of ‘their work’ only if B1 gained.

Unsupported correct answer gains final B1 only.

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