Maclaurin 2019 Q2
2. A right-angled triangle has area 150 cm2 and the length of its perimeter is 60 cm.
What are the lengths of its sides?
Maclaurin Olympiad 2019, Question 2. © UK Mathematics Trust. Original paper on ukmt.org.uk
Answer: 15 cm, 20 cm and 25 cm
Let the sides of the triangle adjacent to the right angle be \(a\) cm and \(b\) cm. Since the area is 150 cm2 we have \(300 = ab\).
The length of the hypotenuse, in cm, is \(60 - (a + b)\), so that, using Pythagoras’ theorem, we have
After expanding and simplifying, we get
and so, substituting \(300 = ab\), we obtain \(a + b = 35\). It follows that \(a\) and \(b\) are roots of the equation \(x^2 - 35x + 300 = 0\), which we may factorise as \((x - 20)(x - 15) = 0\). Therefore \(a\) and \(b\) are 15 and 20, in either order.
Hence the sides of the triangle have lengths 15 cm, 20 cm and 25 cm.
Solution © UK Mathematics Trust, from the Maclaurin Olympiad 2019 solutions.