Higher November 2022 Paper 5 Q15
15
(a) Simplify.\[\sqrt{3} \times \sqrt{15}\] [2]
(b) Rationalise the denominator and simplify.\[\frac{40}{\sqrt{15}}\] [3]
(c) Work out.\[27^{\frac{4}{3}}\] [2]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(3\sqrt{5}\) final answer | 2 | B1 for \(\sqrt{45}\) or [\(\sqrt{15}\) =] \(\sqrt{5}\sqrt{3}\) | |
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(\frac{8\sqrt{15}}{3}\) or \(\frac{8\sqrt{5}\sqrt{3}}{3}\) final answer | 3 | B2 for \(\frac{40\sqrt{15}}{15}\) or \(\frac{40\sqrt{5}\sqrt{3}}{15}\) or M1 for \(\frac{40}{\sqrt{15}} \times \frac{\sqrt{15}}{\sqrt{15}}\) or better | |
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| 81 | 2 | M1 for \(\sqrt[3]{27}^{\,4}\) soi or B1 for \(\sqrt[3]{27}\) = 3 | |