Higher June 2025 Paper 4 Q12
12 The diagram shows a trapezium.
Not to scale
Calculate the area of the trapezium.
You must show your working. [5]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| 119.8[4] with correct working | 5 | M1 for \(\frac{25.6 - 17.2}{2}\) oe or 4.2 | Correct working requires evidence of at least M2 or M1M1 |
| M2 for \(\sqrt{7^2 - (\textit{their}\,4.2)^2}\) or better or 5.6 or M1 for \([h]^2 + (\textit{their}\,4.2)^2 = 7^2\) or 31.36 | their 4.2 must be an attempt at \(\frac{25.6 - 17.2}{2}\) and must be less than 7 | ||
| M1 for \(\frac{25.6 + 17.2}{2} \times \textit{their height}\) oe | for their height do not allow 7 but condone e.g. 31.36 | ||
| If 0 or 1 scored, instead SC3 for answer 119.8[4] with no or insufficient working | Longer methods must be complete and correct : e.g. M1 for 4.2 as before M1 for e.g. \(\cos^{-1}(4.2 \div 7) = 53.13\ldots\) M1 for e.g. \(7\sin(53.13) = 5.59\ldots\) or 5.6 M1 for area as before | ||