Foundation November 2023 Paper 2 Q24
24 A straight line passes through the points (0, 5) and (2, 13).

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Find the equation of the line in the form \(y = mx + c\). [4]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(y = 4x + 5\) final answer | 4 | B3 for final answer \(4x + 5\) OR B2 for gradient = 4 soi or M1 for \(\frac{13 - 5}{2 - 0}\) oe B1 for \(c\) clearly identified as 5 soi | B2 implied by [\(y =\)] \(4x + c\) M1 could be a right angled triangle on the diagram and their \(\frac{\text{change in } y}{\text{change in } x}\) B1 implied by [\(y =\)] \(mx + 5\) but not by a graph ‘y-intercept = 5’ scores B1 |