Foundation November 2020 Paper 3 Q11
11
\[5(2x + 1) + c(x + d) = 12x - 1\]Work out the value of \(c\) and the value of \(d\). [5]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(c = 2\) final answer \(d = {}^{-}3\) final answer | 5 | B3 for \(c = 2\) and B2 for \(d = {}^{-}3\) OR M4 for \(5 + 2d = {}^{-}1\) oe or M3 for \(10 + c = 12\) or \(5 + cd = {}^{-}1\) or \(10x + cx = 12x\) or M2 for \(10x + 5 + cx + cd\) [\(= 12x - 1\)] oe or M1 for \(10x + 5\) or \(cx + cd\) | Must not come from wrong working Accept e.g. \(d2\) or \(2 \times d\) etc for \(2d\) e.g. \(10x + cx + cd = 12x - 6\) |