Foundation November 2020 Paper 3 Q10
10 Sundip is going on holiday.
She wants to change £400 into euros(€).
Bank A will change her £400 into €452.
Bank B changed £250 into €280 for Sundip’s friend.
It will use the same rate to change Sundip’s £400 into euros.
At which bank will Sundip receive the most euros and by how many?
Show your working. [5]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| [Bank] A and 4 with correct working | 5 | M1 for 280 ÷ 250 soi 1.12 or 0.12 M1 for 400 × their 1.12 oe soi 448 M1 for 452 – their 448 A1 dep for their A OR M1 for 280 ÷ 250 soi 1.12 M1 for 452 ÷ 400 soi 1.13 M1 for (their 1.13 – their 1.12) × 400 A1dep for their A If 0 or M1 scored, SC2 for A and 4 or If 0 scored, SC1 for their A and wrong difference with subtraction seen | Correct working requires at least M2 Accept 12% [of 250] seen. oe 0.12 × 400 = 48, 400 + 48 A1 for [Bank] A is dep M3 their A is correct bank from identified 452 – their 448 ALTERNATIVE FORM OF METHOD Reduction to common amount \(\ne 1\) Marks only for e.g. 50 common M1 for 250 ÷ 5 and 280 ÷ 5 (50/56) M1 for 400 ÷ 8 and 452 ÷ 8 (50/56.5) M1 for (their 56.5 – their 56) × 8 A1 for [Bank] A is dep M3 their A is correct bank from identified (their 1.13 – their 1.12) × 400 If there is evidence for M1 only and SC2 is available, award only SC2 A value for A – a value for B seen or A value for B – a value for A seen |
Appendix
Exemplar responses for Q10
| Response | Mark |
|---|---|
| ALTERNATIVE METHOD | |
| M1 for 250 ÷ 5 = 50 and 280 ÷ 5 = 56 M1 for 400 ÷ 8 = 50 and 452 ÷ 8 = 56.5 M1 for 0.5 × 8 This is fine as the two amounts are reduced to a common amount of 50 | 3 |
| M0 for 250 ÷ 5 = 50 and 280 ÷ 5 = 56 M0 for 400 ÷ 10 = 40 and 452 ÷ 10 = 45.2 M0 for (45.2 – 40) × 10 This scores no marks as the amounts reduced to are not common. We must consider the whole method to be able to award marks | 0 |