Foundation November 2019 Paper 2 Q23
23 A straight line with gradient 4 passes through the point (1, 5).
Find the equation of the line in the form \(y = mx + c\). [3]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(y = 4x + 1\) final answer | 3 | B2 for final answer \(4x + 1\) OR M2 for using (1, 5) correctly in \(y = 4x + c\) oe or M1 for \(y = 4x + c\) oe or \(y = 4x + k\) oe \(k\) any numerical value | Allow equivalent 3 term equation for 3 marks If \(y = 4x + c\) and \(y = mx + 4\) are seen, mark as choice |