Foundation November 2017 Paper 1 Q19
19 In the diagram below, ABCD is a trapezium.
Not to scale
Length AE is 37.5 cm.
DE = CF
Find the value of angle \(x\). [6]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| 38.7 | 6 | B3 for 50 for DE or CF nfww Or M1 for \(62.5^2 - 37.5^2\) M1 for \(\sqrt{62.5^2 \pm 37.5^2}\) And B3 FT for \(\sin^{-1}\left(\dfrac{\textit{their } 50}{80}\right)\) correctly evaluated or M2 FT for \(\sin^{-1}\left(\dfrac{\textit{their } 50}{80}\right)\) or M1 FT for \(\sin\) [\(x\)] = \(\dfrac{\textit{their } 50}{80}\) | Allow 39 May be in correct place on diagram 2500 implies M1 |