Foundation June 2023 Paper 3 Q20
20 New cars reduce in value once they have been bought.
Zayn buys a new car for £17 000.
They see this table in a magazine.
| Year | Loss in value compared to the start of the year |
|---|---|
| Year 1 | 15% |
| Year 2 | 10% |
Zayn says
According to this table, the value of my car will be £12 750 at the end of Year 2.
Show that Zayn is not correct. [4]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(17\,000 \times 0.85 \times 0.9\) oe | M3 | M2 for \(17\,000 \times \dfrac{100 - 15}{100}\) oe soi 14 450 or M1 for \(17\,000 \times \dfrac{15}{100}\) oe soi 2550 and M1 for their \(14\,450 \times \dfrac{100 - 10}{100}\) oe | Allow subtractions the wrong way round if intention clear For non-calculator methods, see appendix N/C methods allow layout to imply addition Labels (correct values) e.g. M1 10% = 1700, 5% = 850, 15% = 2550 (incorrect values) M0 10% = 1750 ✗, 5% = 875, 15% = 2625 M1 10% = 1700, 5% = 850, 15% = 1550 ✗ Condone slip in addition Accept any value except 17 000 for their 14 450 After M0 accept 17 000 for their 14 450 |
| [final value =] 13 005 | B1 | Accept 13 000 for B1 after M3 | |
Appendix
Non Calculator methods for percentages.
Labels only
This is when labels such as 10% = are used.
If only labels are used the final answer scores full marks if it is correct.
Condone a numerical slip if the answer is correct.
If there is an error in the values and so the final answer is incorrect this cannot score method marks
e.g. Find 65% of 60
Method scoring M1A1
10% = 6
5% = 3
50% = 30
65% = 39 ✓ M1A1
10% = 6
5% = 4 ✗ condone this slip as answer correct
50% = 30
65% = 39 ✓ M1A1
Method scoring M0A0
10% = 6
5% = 4 ✗ M0 Do not condone this slip as answer incorrect
50% = 30
65% = 40 ✗
Build up method
This is where the candidate finds the percentages to build up to the required value but shows the operations used.
e.g. Find 65% of 60
10% = \(60 \div 10 = x\)
5% = \(x \div 2 = y\)
50% = \(x \times 5 = z\)
65% = \(x + z + y\)
Because the operations have been shown and they are correct, if there is an error in one of \(x\), \(y\) or \(z\), method marks can still be earned