Foundation June 2023 Paper 2 Q4
4
(a) Complete this statement by writing the missing value in the box.\[\frac{17}{5} = 3\frac{\boxed{\phantom{0}}}{5}\] [1]
(b) Write \(2\frac{1}{4}\) as an improper fraction. [1]
(c) Work out.
\(\dfrac{4}{7} - \dfrac{5}{14}\) [2]
(d) Work out, giving your answer as a fraction in its simplest form.
\(\dfrac{2}{5} \times \dfrac{15}{16}\) [2]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| 2 | 1 | ||
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(\dfrac{9}{4}\) | 1 | Accept equivalent improper fractions. | |
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(\dfrac{3}{14}\) oe | 2 | M1 for \(\dfrac{8}{14}\) or \(\dfrac{8k}{14k} - \dfrac{5k}{14k}\) | e.g \(\dfrac{56}{98} - \dfrac{35}{98}\) isw attempts to convert after correct answer seen |
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(\dfrac{3}{8}\) final answer | 2 | M1 for \(\dfrac{30}{80}\) or equivalent fraction or for correct cancelling of 2 and 16 and 5 and 15 | i.e. \(\dfrac{1}{1}\) x \(\dfrac{3}{8}\) |