Foundation June 2017 Paper 3 Q8
8
(a) Harry needs dollars to go on holiday.
He can buy $50 for £40.
He can buy $50 for £40.
How much will $720 cost at the same rate? [2]
(b) Tony returns from holiday with these notes.
| Note | Number of notes |
|---|---|
| €50 | 2 |
| €20 | 4 |
| €10 | 9 |
| €5 | 12 |
The exchange rate is £1 = €1.17.
Work out how much he will get in total when he changes these notes. [4]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| 576 | 2 | M1 for [$1=] \(40 \div 50\) or [0].8 or \(720 \div 50\) soi 14.4[0] or \(50 \div 40\) or 1.25 oe or M1 for full scaling method with correct processes (may be implied by correct values) at each stage | eg [$]50 is [£][40] (process) 100 is [80] (\(\times\) 2) 200 is [160] (\(\times\) 2) 20 is [16] (\(\div\) 10) And sum 200, 200, 200, 100 and 20 |
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| 282 or 282.03 or 282.04 or 282.05 final answer | 4 | M1 for multiplying four note values by the correct number of notes soi by values shown in final column of scheme M1 for dividing a value in euros by 1.17 soi by values shown in final column of scheme M1 for adding four sums of money of the same currency (one from each note value) | Find total of euros \(50 \times 2\) (= 100) \(\div\) 1.17 (=85.47...) \(20 \times 4\) (= 80) \(\div\) 1.17 (=68.37...) \(10 \times 9\) (= 90) \(\div\) 1.17 (=76.92...) \(5 \times 12\) (=60) \(\div\) 1.17 (=51.28...) 100 + 80 + 90 + 60 = [€]330 \(330 \div 1.17\) (=282.05...) Find each denomination in £ 50 \(\div\) 1.17 (=42.73... 42.73 or 42.74) 20 \(\div\) 1.17 (=17.09... 17.09 or 17.10) 10 \(\div\) 1.17 (=8.54... 8.54 or 8.55) 5 \(\div\) 1.17 (=4.273... 4.27 or 4.28) \(42.74 \times 2\) (=85.48) \(17.09 \times 4\) (=68.36) \(8.55 \times 9\) (=76.95) \(4.27 \times 12\) (=51.24) Total = 282.03 |