Foundation June 2017 Paper 2 Q2
2
(a) Work out.
(i) \(6\dfrac{1}{2} + \dfrac{3}{4}\) [1]
(ii) \(\dfrac{4}{7}\) of 63 [2]
(b) Show that \(\dfrac{4}{5}\) is bigger than \(\dfrac{7}{9}\). [2]
(c) Find a fraction which is bigger than \(\dfrac{1}{5}\) and smaller than \(\dfrac{1}{4}\). [2]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| (i) \(7\frac{1}{4}\) oe | 1 | Accept eg \(\dfrac{58}{8}\) ISW Do not accept eg \(6\dfrac{5}{4}\) | |
| (ii) 36 | 2 | M1 for \(63 \div 7\) soi | Implied by [\(\dfrac{1}{7}\) of 63] = 9 \(\dfrac{63}{7}\) not enough for M1 without 9 or division sign or bus stop eg \(7\overline{)63}\) |
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| [\(\dfrac{4}{5} =\)] \(\dfrac{36}{45}\) and [\(\dfrac{7}{9} =\)] \(\dfrac{35}{45}\) oe or [\(\dfrac{4}{5} =\)] 0.8 and [\(\dfrac{7}{9} =\)] 0.77… or 0.78 | 2 | M1 for correct equivalent fraction or decimal to \(\dfrac{4}{5}\) or \(\dfrac{7}{9}\) ISW Or M1 for finding \(\dfrac{4}{5}\) and \(\dfrac{7}{9}\) of a common multiple of 5 and 9 | Accept any valid complete comparison Condone equivalent percentage. Accept \(0.\dot{7}\) |
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| Any fraction \(n\) st \(0.2 \lt n \lt 0.25\) such as \(\dfrac{9}{40}\) | 2 | M1 for either a fraction equivalent to 0.2 and a fraction equivalent to 0.25 seen, where the denominators or the numerators are the same e.g. \(\dfrac{8}{40}\) and \(\dfrac{10}{40}\) seen or [\(\dfrac{1}{5} =\)] 0.2 and [\(\dfrac{1}{4} =\)] 0.25 seen or \(n\) st \(0.2 \lt n \lt 0.25\) where \(n\) not a fraction | Accept equivalent percentages Eg \(\dfrac{4.5}{20}\) |