June 2022 Paper 3 Q1
1 Solve the equation \(|2x - 3| = 9\). [3]
| Scheme | Marks | AO |
|---|---|---|
| \(x = 6\) | B1 | 1.1 |
| \(|2x - 3| = 9 \Rightarrow 2x - 3 = -9\) | M1 | 1.1a |
| \(x = -3\) | A1 | 1.1 |
| [3] |
Notes
B1: B0 for \(|x| = 6\) unless replaced with \(x = 6\)
M1: oe e.g. \((2x - 3)^2 = 81\) or \(2x - 3 = \pm 9\)
M0 for \((2x - 3)^2 = 9\)
A1: A0 for \(|x| = -3\) unless replaced with \(x = -3\)
The correct answer implies the previous M mark
Two marks maximum if more than two answers given