June 2023 Paper 2 Q16
16 Research conducted by social scientists has shown that 16% of young adults smoke cigarettes.
Two young adults are selected at random.
(a) Determine the probability that one smokes cigarettes and the other doesn’t. [2]
The same research has also shown that
- 75% of young adults drink alcohol.
- 66% of young adults drink alcohol, but do not smoke cigarettes.
(b) Determine the probability that a young adult selected at random does smoke cigarettes, but does not drink alcohol. [2]
(c) A young adult who drinks alcohol is selected at random. Determine the probability that this young adult smokes cigarettes. [2]
(d) Using your answer to part (c), explain whether the event that a young adult selected at random smokes cigarettes is independent of the event that a young adult selected at random drinks alcohol. [2]
| Scheme | Marks | AO |
|---|---|---|
| \(0.16 \times 0.84 \times 2\) or B(2, 0.16) or B(2, 0.84) seen or \(1 - (0.84^2 + 0.16^2)\) | M1 | 1.1 |
| \(\frac{168}{625}\) or 0.2688 or 0.269 or 0.27 cao | A1 | 1.1 |
| [2] |
Notes
M1: condone omission of 2
allow recovery from bracket error
A1: mark the final answer
allow SC1 for correct answer unsupported
| Scheme | Marks | AO |
|---|---|---|
| \(0.75 - 0.66 = 0.09\) | M1 | 3.1a |
| \([0.16 - 0.09 =]\ 0.07\) isw | A1 | 1.1 |
| [2] |
Notes
M1: allow 0.09 embedded in correct place in Venn diagram or contingency table; allow M1 for 9%
A1: allow SC1 for correct answer unsupported
| Scheme | Marks | AO |
|---|---|---|
| \(\frac{0.09}{0.75}\) | M1 | 3.1a |
| 0.12 | A1 | 1.1 |
| [2] |
Notes
M1: M0 for 0.12 from wrong working
A1: allow SC1 for correct answer unsupported
| Scheme | Marks | AO |
|---|---|---|
| \(0.12 \neq 0.16\) | M1 | 2.1 |
| so not independent | A1 | 2.2a |
| [2] |
Notes
A1: if M0 allow SCB1 for \(0.16 \times 0.75 \neq 0.09\) so not independent