Higher November 2018 Paper 2 Q12
12. Jenny is setting up a stall offering prizes in a community hall.
She has a bag of white, red, green and black balls.
All the balls in the bag are the same size.
A player pays £1 to select a ball at random.
The probability that a player selects:
- a white ball is 0·4,
- a red ball is 0·2,
- a green ball is 3 times the probability of selecting a black ball.
When either a black ball or a red ball is selected the player will win a prize.
The prizes are:
- £2.50 for selecting a black ball,
- £1.50 for selecting a red ball.
Any ball selected is to be placed back into the bag before the next player has a go.
If 300 players select a ball, show that Jenny can expect to make a profit in excess of £125. [4]
| Scheme | Marks | Comments |
|---|---|---|
| Probability of black is 0.1 | B1 | |
| Profit \(300 - 300\times0.1\times2.50 - 300\times0.2\times1.50\) \((= 300 - 75 - 90)\) or \(300\,(0.7\times1 - 0.1\times1.5 - 0.2\times0.5)\) \((= 300\,(0.7 - 0.15 - 0.1)\)\()\) | M2 | May be seen in stages, must show full calculation method eventually FT ‘their 0.1’ provided it is clearly the probability of selecting a black ball M1 for sight of \(300\times0.1\times2.50\) or \(300\times0.2\times1.50\) (=165), or if one incorrect product within \(300\,(0.7\times1 - 0.1\times1.5 - 0.2\times0.5)\) |
| (£)135 | A1 | Only continue with FT ‘their 0.1’ provided ‘their 135’ > 125 |
| (4) |
Corrected by Westie's Workshop
- The board's mark scheme printed “\((= 300\,(0.7 - 0.15 - 0.1)\)”. Changed to “\((= 300\,(0.7 - 0.15 - 0.1))\)” because a closing bracket was missing.
Original: see the board's mark scheme PDF (link above).