Higher June 2022 Paper 2 Q19
19.
(a) Find the equation of the line parallel to \(4x = 5 - y\) which passes through the point (1, −1).
Give your answer in the form \(y = mx + c\). [3]
Give your answer in the form \(y = mx + c\). [3]
(b) Find the equation of the line perpendicular to \(y = 1 - \dfrac{x}{5}\) which passes through the point (0, 7). [2]
| Scheme | Marks | Comments |
|---|---|---|
| (gradient =) \(-4\) | B1 | May be seen as: \(y = -4x + c\) or \(4x = c - y\) where \(c\) may be numeric but \(c \ne 5\) |
| \(-1 = -4(1) + c\) or \(4(1) = c - (-1)\) oe | M1 | FT ‘their −4’ |
| \(y = -4x + 3\) or \(y = 3 - 4x\) \(y = -4x + 5\) is B0 M0 A0 (the original) \(y = -4x - 3\) probably from using (-1, 1) check B1 M0 A0 | A1 | CAO If gradient of 4 used, award M1 and SC1 for an answer of \(y = 4x - 5\) if appropriate working seen |
| Scheme | Marks | Comments |
|---|---|---|
| \(y = 5x + 7\) oe | B2 | B1 for gradient = 5, may be seen in an equation e.g. \(y = 5x + c\) |
| (5) |