Higher June 2019 Paper 1 Q9
9. Rearrange \(6(x + y) = 8x - 5\) to make \(x\) the subject. [3]
| Scheme | Marks | Comments |
|---|---|---|
| \(6x + 6y = 8x - 5\) | B1 | FT until 2nd error; Expands brackets |
| \(6y + 5 = 8x - 6x\) | B1 | FT; collects terms; implies first B1 |
| \(x = \dfrac{6y + 5}{2}\) | B1 | FT; divides; mark final answer; final answer may be unsimplified e.g. \(x = \dfrac{-5 - 6y}{6 - 8}\) |
| (3) |