Foundation November 2024 Paper 2 Q17
17. A right-angled triangle and a square are shown below.
Diagram not drawn to scale
The perimeter of the triangle is equal to the perimeter of the square.
Calculate the area of the square.
You must show all your working. [6]
Area of square = ………… \(\text{cm}^2\)
| Scheme | Marks | Comments |
|---|---|---|
| No marks are awarded for an answer of 15.3 obtained from use of a scale drawing. | ||
| (h2 =) \(7.2^2 + 13.5^2\) | M1 | May be implied in later working. Provided not spoiled by answers of 20.7, 20.72 or 428.49. |
| h2 = 234.09 or (h =) \(\sqrt{234.09}\) | A1 | |
| (h = ) 15.3 | A1 | FT from M1 for the correctly evaluated square root of ‘their 234.09’ provided ‘their answer’ > 13.5 (cm) Must be from correct working |
| (Area of square = ) ((7.2 + 13.5 + 15.3) ÷ 4)2 | M2 | FT ‘their 15.3’ provided M1 previously awarded. M1 for (7.2 + 13.5 + 15.3) ÷ 4 (= 9) |
| 81 (cm2) | A1 | FT If no marks award SC1 for the correct evaluation of ((13.5 + 7.2 + 'their 15.3') ÷ 4)2 |
| (6) |
Corrected by Westie's Workshop
- The board's mark scheme printed “(13.5 + 7.2 + 'their 15.3') ÷ 4)²”. Changed to “((13.5 + 7.2 + 'their 15.3') ÷ 4)²” because an opening bracket was missing.
Original: see the board's mark scheme PDF (link above).