Foundation November 2018 Paper 1 Q12
12.
(a) Circle all the fractions in the list that are equivalent to \(\frac{20}{30}\). [2]
\(\dfrac{15}{25}\) \(\dfrac{2}{3}\) \(\dfrac{30}{45}\) \(\dfrac{3}{2}\) \(\dfrac{4}{6}\)
(b)
Sangita thinks that \(3 \times \frac{1}{7} = \frac{3}{21}\).
Explain why Sangita is wrong. [1]
(c) Work out \(\frac{3}{4} + \frac{1}{6}\). [2]
| Scheme | Marks | Comments |
|---|---|---|
| \(\dfrac{2}{3}\) \(\dfrac{30}{45}\) \(\dfrac{4}{6}\) | B2 | B1 for any two correct with none incorrect or for all 3 correct with one extra |
| Scheme | Marks | Comments |
|---|---|---|
| Valid explanation e.g. ‘\(\frac{3}{21}\) is the same as \(\frac{1}{7}\) (not 3 times it).’ | E1 | Accept e.g. ‘\(3 \times \frac{1}{7} = \frac{3}{7}\) (not \(\frac{3}{21}\))’ or ‘\(\frac{3}{21} = \frac{1}{7}\) (not \(\frac{3}{7}\))’ |
| Scheme | Marks | Comments |
|---|---|---|
| \(\frac{9}{12} + \frac{2}{12}\) | M1 | or equivalent calculation with correct common denominator |
| \(\frac{11}{12}\) or equivalent | A1 | |
| (5) |