S4 June 2016 Q2
2. The weights of piglets at birth, \(M\) kg, are normally distributed \(\mathrm{N}(\mu, \sigma^2)\)
A random sample of 9 piglets is taken and their weights at birth, \(m\) kg, are recorded. The results are summarised as
\[\sum m = 11.6 \qquad \sum m^2 = 15.2\]Stating your hypotheses clearly, test at the 5% level of significance
| Scheme | Marks |
|---|---|
| \(\mathrm{H}_0 : \mu = 1.2 \quad \mathrm{H}_1 : \mu \gt 1.2\) | B1 |
| \(t_8(5\%) = 1.860\) | B1 |
| \(\bar{m} = 1.28888\ldots\) | B1 |
| \(t = \dfrac{1.28\ldots - 1.2}{\sqrt{\dfrac{0.031111}{9}}} = 1.511\) awrt 1.51 | M1 A1ft A1 |
| Not significant. There is not sufficient evidence that the mean weight of piglets is greater than 1.2 kg | A1 |
| (7) |
Notes
B1 both hypotheses
M1 for attempting the correct statistic
A1ft follow through their s2
A1 awrt 1.51
| Scheme | Marks |
|---|---|
| \(\mathrm{H}_0 : \sigma^2 = 0.09 \quad \mathrm{H}_1 : \sigma^2 \ne 0.09 \qquad [\mathrm{H}_0 : \sigma = 0.3 \ \ \mathrm{H}_1 : \sigma \ne 0.3]\) | B1 |
| \(s^2 = \dfrac{15.2 - 9 \times \left(\dfrac{11.6}{9}\right)^2}{8} = 0.031111\) | B1 |
| \([\chi^2_8(0.025) = 17.535] \quad \chi^2_8(0.975) = 2.18\) | B1 |
| Critical region \(\dfrac{(n-1)s^2}{\sigma^2} \sim \chi^2_8\) test statistic = 2.7654… awrt 2.77 | M1A1 |
| 2.77 is not in the critical region. There is no evidence that the standard deviation of the weights of piglets is different to 0.3 | A1 |
| (6) | |
| (13 marks) |
Notes
B1 both hypotheses, must be two tail
B1 awrt 0.0311
B1 NB allow 2.733 for one tail hypotheses. (no hypotheses gains B0)
M1 for a correct test statistic
NB one tail test can get B0 B1 B1 (2.733)B0 M1 A1 A1
(Corrected from the printed mark scheme: the upper critical value is printed as \(\chi^2_8(0.25) = 17.535\); it is the upper 2.5% point, \(\chi^2_8(0.025)\).)