S2 January 2013 Q1
1.
The probability of any one letter being delivered to the wrong house is 0.01
On a randomly selected day Peter delivers 1000 letters.
Give your answer to 4 decimal places. (3)
| Scheme | Marks |
|---|---|
| \(n\) large | B1 |
| \(p\) small | B1 |
| (2) |
Notes
B1 Accept \(n\) (the number of trials) large / high / big / \(n \gt 50\) (accept any number larger than 50)
B1 Accept \(p\) (the probability) small / close to 0 / \(p \lt 0.2\) ( accept any number less than 0.2). Do not accept low.
These must appear in part (a).
| Scheme | Marks |
|---|---|
| Let \(X\) be the random variable the number of letters delivered to the wrong house | |
| \(X \sim \mathrm{B}(1000, 0.01)\) | |
| Po(10) | B1 |
| \(\mathrm{P}(X \geqslant 4) = 1 - \mathrm{P}(X \leqslant 3)\) | M1 |
| \(= 1 - 0.0103\) | |
| \(= 0.9897\) | A1 |
| (3) | |
| (5 marks) |
Notes
B1 writing or using Po(10)
M1 using a Poisson (\(\lambda\) need not equal 10) and for writing or using \(1 - \mathrm{P}(X \leqslant 3)\). (Do not accept writing \(1 - \mathrm{P}(X \lt 4)\) unless they have used \(1 - \mathrm{P}(X \leqslant 3)\)).
A1 0.9897 cao must be 4 dp
NB
An awrt 0.990 on its own gains B0M0A0 unless there is evidence that Po(10) is used. In which case it gets B1M1A0
Using B(1000,0.01) gives 0.989927…. and gains B0M0A0