S1 June 2013 (R) Q5
5. A researcher believes that parents with a short family name tended to give their children a long first name. A random sample of 10 children was selected and the number of letters in their family name, \(x\), and the number of letters in their first name, \(y\), were recorded.
The data are summarised as:
\[\sum x = 60, \quad \sum y = 61, \quad \sum y^2 = 393, \quad \sum xy = 382, \quad \mathrm{S}_{xx} = 28\]The researcher decides to add a child with family name “Turner” to the sample.
Given that the addition of the child with family name “Turner” to the sample leads to an increase in \(\mathrm{S}_{yy}\)
| Scheme | Marks |
|---|---|
| \(\mathrm{S}_{yy} = 393 - \dfrac{61^2}{10} = \underline{\mathbf{20.9}}\) | M1A1 |
| \(\mathrm{S}_{xy} = 382 - \dfrac{61\times 60}{10} = \underline{\mathbf{16}}\) | A1 |
| (3) |
Notes
M1 for a correct expression for \(\mathrm{S}_{yy}\) or \(\mathrm{S}_{xy}\)
1st A1 for \(\mathrm{S}_{yy} = 20.9\)
2nd A1 for \(\mathrm{S}_{xy} = 16\)
| Scheme | Marks |
|---|---|
| \([r =]\ \dfrac{\text{"}16\text{"}}{\sqrt{\text{"}20.9\text{"}\times 28}}\) | M1 |
| \(= 0.66140\ldots\) awrt 0.661 | A1 |
| (2) |
Notes
M1 for a correct expression for \(r\) – ft their 20.9 (provided it is > 0) and their 16. Use of 382 for 16 or 393 for 20.9 is M0
A1 for awrt 0.661
| Scheme | Marks |
|---|---|
| Researcher’s belief suggests negative correlation, data suggests positive correlation | B1 |
| So data does not support researcher’s belief | dB1 |
| (2) |
Notes
1st B1 for a suitable reason contrasting belief with data. They must state the sign (positive or negative) of the correlation of data or the belief and imply the other is opposite
2nd dB1 Dependent on a correct reason for saying it does not support the claim
e.g. State “does not support the belief because data has positive correlation” scores B1B1 BUT State “does support the belief because data has positive correlation” scores B0B0
| Scheme | Marks |
|---|---|
| New \(x\) equals \(\bar{x} = 6\) | B1 |
| Since \(\mathrm{S}_{xx} = \sum(x - \bar{x})^2\) the value of \(\mathrm{S}_{xx}\) is the same = 28 | dB1 |
| (2) |
Notes
1st B1 for clearly stating that new value of \(x = (6 =)\) mean
2nd dB1 Dep. on 1st B1 for a reason that shows \(\mathrm{S}_{xx}\) is unchanged e.g. extra term is 0 so \(\mathrm{S}_{xx}\) is the same
ALT 1st B1 for seeing \(\sum x = 66\) and new \(\sum x^2 = 424\) (or \(388 + 6^2\)) and attempt at \(\mathrm{S}_{xx}\)
2nd B1 for showing \(\mathrm{S}_{xx} = 28\) with \(n = 11\) and no incorrect working seen and a final comment
| Scheme | Marks |
|---|---|
| \(\mathrm{S}_{xy} = \sum(x - \bar{x})(y - \bar{y}) = \sum(x - \bar{x})y\) so the new term will be zero (since mean = \(x\)) and since \(\mathrm{S}_{yy}\) increases | B1 |
| So \(r\) will decrease | dB1 |
| (2) | |
| (11 marks) |
Notes
1st B1 for a clear reason that mentions \(\mathrm{S}_{xy}\) is the same and the increase in \(\mathrm{S}_{yy}\). Saying that \(r\) increases or stays the same is B0B0
2nd dB1 Dependent on 1st B1 for saying \(r\) will decrease.