M4 June 2007 Q3
3.

A framework consists of two uniform rods \(AB\) and \(BC\), each of mass \(m\) and length \(2a\), joined at \(B\). The mid-points of the rods are joined by a light rod of length \(a\sqrt{2}\), so that angle \(ABC\) is a right angle. The framework is free to rotate in a vertical plane about a fixed smooth horizontal axis. This axis passes through the point \(A\) and is perpendicular to the plane of the framework. The angle between the rod \(AB\) and the downward vertical is denoted by \(\theta\), as shown in Fig. 1.

| Scheme | Marks |
|---|---|
| \(V = -mga\cos\theta - mg(2a\cos\theta + a\sin\theta)\) | M1A1A1 |
| \(= -mga(3\cos\theta + \sin\theta)\quad (+const)\ *\) | A1 |
| (4) |
Notes
M1 Expression for the potential energy of the two rods. Condone trig errors. Condone sign errors. BC term in two parts
A1 correct expression for AB
A1 correct expression for BC
A1 Answer as given.
| Scheme | Marks |
|---|---|
| \(\dfrac{dV}{d\theta} = -mga(-3\sin\theta + \cos\theta)\) | M1A1 |
| \(= 0\ \Rightarrow\ \tan\theta = \dfrac{1}{3}\) | M1 |
| \(\Rightarrow \theta = 0.32(1)^c\) or \(18.4^o\) accept awrt | A1 |
| (4) |
Notes
M1 Attempt to differentiate V. Condone errors in signs and in constants.
A1 Derivative correct
M1 Set derivative = 0 and rearrange to a single trig function in \(\theta\)
A1 Solve for \(\theta\)
or M1A1 find the position of the center of mass
M1A1 form and solve trig equation for \(\theta\)
| Scheme | Marks |
|---|---|
| \(\dfrac{d^2V}{d\theta^2} = -mga(-3\cos\theta - \sin\theta)\) | M1A1 |
| \(= mga(3\cos\theta + \sin\theta)\) | |
| Hence, when \(\theta = 0.32^c\), \(\ \dfrac{d^2V}{d\theta^2} \gt 0\) | M1 |
| i.e. stable | A1 |
| (4) | |
| (12 marks) |
Notes
M1 Differentiate to obtain the second derivative
A1 Derivative correct
M1 Determine the sign of the second derivative
A1 Correct conclusion. cso
Or: M1 Find the value of \(\dfrac{dV}{d\theta}\) on both sides of the minimum point
A1 signs correct
M1 Use the results to determine the nature of the turning point
A1 Correct conclusion, cso.
These 4 marks are dependent on the use of derivatives